![]() But the relay will fast cut off the load when the input falls to AC 198V by can adjust potentiometer -VR1. This motor protection circuit will be starting with input voltage AC 215 V. Then wiring the different positions.įigure 4 Actual size of single sided copper PCB layout. Do not hurry, especially for pins to make sure the correct position. Then soldering all parts on PCB as Figure 5, to begin with soldering low devices first.įor example resistors, diodes then put higher parts down until connecting a transformer and more parts. Buildingīefore make the PCB as Figure 4 as copper PCB layout. Therefore, it is virtually no voltage to bias the Q2 As a result LED goes out. The transistor Q2 will drive LED to alert when under-voltage until electric devices cannot work.īut in normal Q1 will ON cause the voltage across Q2 is low so most current will flow to ground. Thus in this circuit, we use voltage from the 15.8 volts power supply, then flow through the divider circuit of R1 and R2 cause have an 8.7 volts supply of IC1 only. The disadvantage of this IC is not able to tolerate the higher voltage of 16 volts. The output voltage is 0.6 volts which may make the transistor can work. As a result transistor Q1 can not work absolutely.īut the common comparator ICs in not work state. Reasons to Use IC1-CA3130 BecauseWhen conditions do not work, to make the output voltage is near 0 volts really. So relay pulls in as Graph of time function in Figure 3. Restarting with increasing AC voltage about 215 volts (as setting). If the main have ripple voltage,this will not works because the motor may be damaged. This is a special feature, it will cut off the load at once, when the AC main is under voltage into setting value. ![]() We will also connect the resistor-R5 across pin 6 and pin 3 of IC1, to set circuit in Schmitt trigger form. It may cause IC1, the relay-RY1 works with the error. Pin 3 will be connected to capacitor C3 to reduce the fluctuating voltage to smooth. So this will apply a relay pulls in and connects AC electrical current to the motor or AC load.įigure 2 The schematic of Motor burn out and under-voltage protection We will set this voltage slightly lower than the reference voltage. It will compare voltage between the reference voltage of ZD1- 3.6 volts the Zener diode, and input voltage from pin 3 of IC1 this voltage is divided by resistor-R4 and VR1. There is an op-amp-IC1 as an input voltage comparator. Ideally, block diagram in Figure 1.įigure 1 the block diagram The working of the motor protection circuitįigure 2 is a schematic of this project. Until the voltage is restored to its original condition. And AC-line fall down lower than 10% of normal voltage the relay will cut off the load at once. Can be set to cut no-off in the voltage during the 168-227V.Īs AC main in normal level, the relay will be connect to apply AC line to motor. Relay will not work and the LED is a warning. The principle is simple, it will check for voltage at all times. It will protect the AC motor burn out. Because of under voltage input. Should be careful polarity of the diodes, Zener diodes, electrolytic capacitors types Induction Motor Protection Circuit and working All equipment will be soldered onto the PCB purpose. ZD2: 6.8V 0.5W Zener Diode C1: 470♟ 25V Electrolytic Capacitors C2,C3: 0.1♟ 63V Polyester Capacitor LED: as you like.IC2: LM7812_12V 1A DC voltage regulator.IC1: LM324_ Quad/ 1MHz/ Operational Amplifiers.LED1 display when power or low power over a specified. The two components can be specified by VR1, VR2. ![]() The IC2/2 serves to detect the lower voltage. Thus cutting off power from the load instantly. Pressure acts edge IC2/1 High Voltage Detector, High Voltage ICs, if this current work to the Q1 and relay function, it works with. Or input pin of IC1, a loan IC Rex bit computing to 12-volt power supply is fixed to the IC2. Then, through the C1 and C2 to the power filter smoothing. To convert the voltage, alternating current to direct current. It serves to reduce the pressure remaining 12 volts, through a D1-D4 connected to Direct rectifier bridge circuit. From the circuit when the voltage is 220 volts AC through a transformer T1. ![]()
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